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blog/26-04-26/x509-certificates-in-js---encrypt-decrypt-data/x509-certificates-in-js---encrypt-decrypt-data.html

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@@ -115,9 +115,9 @@ <h1 slot=title class=title>
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<div class=blog-text>
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<h4>
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notes :
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</h4>
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<p>
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private keys :
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</p>
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<div class=blog-text>
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<h3>what size rsa keys do i need to encrypt an aes key of 256 bits</h3>
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<h3 class=blog-hdr>
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what size rsa keys do i need to encrypt an aes key of 256 bits
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</h3>
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<p>To safely encrypt a 256-bit AES key using RSA, you should use an RSA key size of at least 2048 bits,
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though 3072 bits or 4096 bits is highly recommended for modern applications requiring long-term security.</p>
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<p>The reason for this requires looking at how RSA and AES work together, as well as the strict physical limits of RSA encryption.</p>
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<p><strong>4096-bit RSA</strong> provides roughly <strong>140+ bits</strong> of effective security strength.</p>
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<p>While mathematically a 3072-bit or 4096-bit RSA key is technically required to get closer to the massive security margin of a 256-bit AES key,
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<strong>2048-bit is the absolute bare minimum</strong> allowed by modern cryptographic standards.</p>
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<h2>Padding Overhead</h2>
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<h4>
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Padding Overhead
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</h4>
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<p>You can easily fit a 256-bit (32-byte) AES key into even the smallest standard RSA key size because of how RSA handles data.</p>
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<p>An RSA key can only encrypt data that is smaller than its own modulus size, minus the required bytes for secure padding (like OAEP).</p>
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<p>Even a 2048-bit RSA key gives you 190 bytes of payload space, which is more than enough room to slot your 32-byte AES key into.</p>
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<h2>Recommendation</h2>
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Recommendation
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</h4>
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<p>Go with 3072-bit if you want the optimal balance between tight security and fast performance,
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or 4096-bit if execution time isn't a bottleneck in your application and you want maximum security.
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Avoid 2048-bit if you are designing a brand-new system from scratch.</p>
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<h3>how does iv length affect things? whats the deal with 96 bits</h3>
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how does iv length affect things? whats the deal with 96 bits
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</h3>
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<p>When dealing with encryption (specifically symmetric encryption like <strong>AES</strong>), the <strong>Initialization Vector (IV)</strong>
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ensures that encrypting the exact same data twice results in two completely different ciphertexts.
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This prevents attackers from spotting patterns in your data.</p>
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| (96 bits) | (32 bits) |
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+------------------------------------+------------------+
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</code></pre>
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<h4>What happens if you use a 96-bit IV?</h4>
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What happens if you use a 96-bit IV?
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</h4>
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<p>If you supply exactly 96 bits, the cryptographic engine simply pads it with a 32-bit counter starting at 1.
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<strong>This is direct, incredibly fast, and requires zero extra computational overhead.</strong></p>
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<h4>What happens if you use any other size (e.g., 128 bits)?</h4>
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What happens if you use any other size (e.g., 128 bits)?
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</h4>
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<p>If you pass an IV that is not 96 bits, the algorithm cannot use it directly. Instead, it has to run your IV through
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a hashing function called GHASH to mathematically compress or stretch it into a 96-bit value first.</p>
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<p>The Downside: This adds extra computation (hurting performance), can subtly introduce a higher risk of IV collisions,
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and can lead to implementation bugs across different programming languages.</p>
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<p>Rule of Thumb for GCM: Always use a 96-bit (12-byte) IV for AES-GCM. Using anything else is less efficient
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and prone to compatibility headaches.</p>
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<h4>What About Other Modes (Like AES-CBC)?</h4>
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What About Other Modes (Like AES-CBC)?
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</h4>
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<p>If you are using an older mode like AES-CBC (Cipher Block Chaining), the rule is different.</p>
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<p>CBC mode requires the IV to be exactly the same size as the cipher's block size.
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Since AES always has a block size of 128 bits, AES-CBC requires a 128-bit (16-byte) IV.</p>

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