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Solution002.java
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66 lines (65 loc) · 2.24 KB
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/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
if (l1 == null && l2 == null) {
return null;
}
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
// resultList, resultNode, resultNext必须初始化,否则编译不通过
ListNode resultList = null; // 返回链表
ListNode resultNode = null; // 头节点
ListNode resultNext = null; // 每次新插入的节点
int carry = 0; // 进位
while(l1 != null && l2 != null){
resultNext = new ListNode(l1.val + l2.val + carry);
carry = resultNext.val / 10; // 计算进位
resultNext.val = resultNext.val % 10; // 计算该位的数值
if (resultList == null) { // 头节点为空,即插入的节点为返回链表的第一个节点时
resultNode = resultNext;
resultList = resultNext;
}
else { // 头节点不为空
resultNode.next = resultNext;
resultNode = resultNext;
}
l1 = l1.next;
l2 = l2.next;
}
while (l1 != null) // 链表l1比链表l2长,处理链表l1的高位
{
resultNext = new ListNode(l1.val + carry);
carry = resultNext.val / 10;
resultNext.val = resultNext.val % 10;
resultNode.next = resultNext;
resultNode = resultNext;
l1 = l1.next;
}
while (l2 != null) // 链表l2比链表l1长,处理链表l2的高位
{
resultNext = new ListNode(l2.val + carry);
carry = resultNext.val / 10;
resultNext.val = resultNext.val % 10;
resultNode.next = resultNext;
resultNode = resultNext;
l2 = l2.next;
}
if (carry > 0) // 最高位产生进位,需要新建节点进行存储
{
resultNext = new ListNode(carry);
resultNode.next = resultNext;
}
return resultList;
}
}