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How to specify the output dir ? #85

Description

@wangzhaode

When I used this action build a iOS project using below code:

  - uses: mxcl/xcodebuild@v1
    with:
      platform: iOS
      action: build
      configuration: release
      working-directory: project/ios
      scheme: XXX

I get the below log:

▸ xcodebuild build
.....
▸ Touching XXX.framework (in target 'XXX' from project 'XXX')
▸ Build Succeeded

Now i want to get XXX.framework and upload, but i can't find a way to set the output dir

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