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19 changes: 19 additions & 0 deletions leetcode3/변지협/v2/3996. Even Number of Knight Moves.py
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'''
1. 아이디어 :
생각해보면 x좌표와 y좌표의 차이가 모두 짝수이거나 모두 홀수이면 도달 가능하다.

2. 시간복잡도 :
o(1)

3. 자료구조/알고리즘 :
'''
class Solution:
def canReach(self, start: list[int], target: list[int]) -> bool:
x,y = start
tx,ty = target

if abs(x - tx) % 2 == abs(y - ty) % 2:
return True
else:
return False