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The spec says an empty array is null. The zero sum divided by zero was NaN.
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Summary
avgof an empty array returnedNaN. The sum is 0 and the length is 0, so the division is0/0.maxandminof an empty array already return null.avg([])now does too.avgof[-1, 3, 4, 5]is still2.75.Test plan
go test -count=1 .avg(empty_list)failed on master (float64(NaN), expected nil) and passes after the change.